Page 156 - New Medley 5 Semester 1

(b) The number 127296 ends with 6, so it is divisible by 2
but not by 5 or 10.

Sum of digits of this number = 1 + 2 + 7 + 2 + 9 + 6

= 27 is a multiple of 3 as well as 9, so the number is
divisible by 3 and 9.

The number is divisible by 2 and 3 both, so it is also

divisible by 6.

The number formed with the last two digits is 96 (i.e.,
a multiple of 4) and the number formed with the last

three digits is 296 (i.e., a multiple of 8), hence the

given number is divisible by 4 as well as 8.

Example 2: Check whether the numbers 43978 and 1234568 are

divisible by 11.
Solution: In 43978, the sum of digits at odd places is 4 + 9 + 8

= 21 and at even places is 3 + 7 = 10. Their difference

21 – 10, i.e., 11 is divisible by 11, so the number 43978
is also divisible by 11.

In 1234568, the sum of digits at odd places is 1 + 3 +

5 + 8 = 17 and at even places is 2 + 4 + 6 = 12. Their
difference 17 – 12, i.e., 5 is neither 0 nor divisible by 11.

So, the number is not divisible by 11.

EXERCISE 3.2

A. State whether the following numbers are divisible by:

1. 2 (a) 24 (b) 371 (c) 884 (d) 4169 (e) 12058

2. 3 (a) 18 (b) 67 (c) 105 (d) 3159 (e) 49578

3. 4 (a) 200 (b) 310 (c) 6472 (d) 12342 (e) 20357

4. 5 (a) 36 (b) 45 (c) 110 (d) 1000 (e) 49875

5. 6 (a) 31 (b) 74 (c) 165 (d) 426 (e) 3594

6. 8 (a) 120 (b) 1046 (c) 5000 (d) 96832 (e) 42596

154