Page 98 - New Medley 4 Semester 2 PDF (Merged)
P. 98
Here, LCM of 3, 6 and 12 is 12 as 12 is a multiple of each
of the denominators.
2 2×4 8 3 3× 2 6 7 7× 1 7
∴ = = , = = , = =
3 3×4 12 6 6× 2 12 12 12 ×1 12
Now, 8 > 7 > 6
8 7 6 2 7 3
So, > > , i.e., > >
12 12 12 3 12 6
2 7 3
Thus, , and are in descending order.
3 12 6
15 16 20
Example 9: Arrange , and in descending order.
4 5 3
15 3 16 1 20 2
Solution: We have = 3 , = 3 and = 6
4 4 5 5 3 3
In these mixed fractions, the whole numbers are 3, 3 and 6,
2 20
so 6 , i.e., is the greatest fraction.
3 3
3 1
Now, compare and .
4 5
By cross-multiplication, we have
3 1
4 5
3 × 5 4 × 1 or 15 > 4
3 1 3 1
∴ > i.e., 3 > 3
4 5 4 5
Hence, fractions in descending order are as follows:
2 3 1
6 > 3 > 3
3 4 5
20 15 16
i.e., > >
3 4 5
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