Page 103 - New Medley 4 Semester 2 PDF (Merged)
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5           3
        Solution:           To convert            and        into like fractions, find the LCM of
                                             12           4

                            their denominators. LCM of 12 and 4 is 12 because 12 is
                            a multiple of 4.

                                                           3       3×3        9
                            Therefore,                         =           =
                                                           4       4× 3       12

                                                    3      5       9      5      9- 5       4      1
                            Now,                       -       =       -      =          =      =
                                                    4     12       12    12       12        12     3

                            (Result should be in the simplest form.)

              Addition and Subtraction of Mixed or Improper Fractions


                                                           1       1            1        2
        Example 15:  Find the sum: (a)  2                     +3  (b)  3            +2
                                                           3       3            4        3

                                      1       1                     1     1 
        Solution:            (a)  2      +3  = (2 + 3) +               +    
                                      3       3                      3    3 


                                   (Add  whole  number  parts  and  fractional  parts
                                   separately)

                                              1 +  1            2       2
                                   = 5 +             = 5 +         =  5
                                                3               3       3
                                                    

                                   (Write whole number parts and fraction together)

                                      1       2                     1     2              1× 3       2×4 
                             (b)   3     +2  = (3 + 2) +               +      = 5 +              +          
                                      4       3                      4    3               4× 3      3×4     
                                                                                          
                                                                                                               
                                               3      8              3+ 8               11        11
                                   = 5 +          +        = 5 +              = 5 +          =5
                                                                      
                                                                                
                                              12     12                12               12        12
                                   Alternative method
                                      1       2     13      8
                                   3     +2  =           +      (Convert into improper fractions)
                                      4       3      4      3

                                       13×3         8× 4
                                   =             +           (Make like fractions)
                                        4× 3        3×4

                                       39      32       39 +32
                                   =        +       =               (Add)
                                       12      12          12                                                 101
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