Page 109 - New Medley 5 Semester 2

  Profit = Selling price – Cost Price or S.P. – C.P.

S.P. = C.P. + Profit and C.P. = S.P. – Profit

  Loss = Cost price – Selling price or C.P. – S.P.

S.P. = C.P. – Loss and C.P. = S.P. + Loss

Example 1: Prashant made a profit of `75 on selling a camera for

`1125. What was the cost price of the camera?

Solution: We have S.P. = `1125 and Profit = `75

As C.P. = S.P. – Profit

\ C.P. = `1125 – `75 = `1050

Example 2: A shopkeeper bought a desert cooler for `5800 and he
incurred a loss of `300 on its sale in off-season. What

was the selling price of the cooler?

Solution: Given, C.P. of the cooler = `5800 and Loss = `300

As S.P. = C.P. – Loss

\ S.P. = `5800 – `300 = `5500

EXERCISE 3.1

A. Find the cost price in each of the following.

1. S.P. = `10, Profit = `1
2. S.P. = `28, Loss = `3

3. S.P. = `150, Loss = `5

4. S.P. = `780, Profit = `50

5. Profit = `605, S.P. = `15800, repairing cost = `300

6. Maintenance = `250, Loss = `100, S.P. = `9100

B. Calculate the profit or loss in the following.

1. C.P. = `55, S.P. = `70

2. C.P. = `110, S.P. = `102

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