Page 136 - New Medley 5 Semester 2

Example 8: Divide 8 km 5 hm 7 dam 7 m by 3.

Solution: km hm dam m

2 8 5 9 2 . 8 5 9 km
3 8 5 7 7 or 3 8 . 5 7 7 km

– 6 – 6
2 5 2 5

– 2 4 – 2 4
1 7 1 7

– 1 5 – 1 5
2 7 2 7

– 2 7 – 2 7
0 0

Thus, 8 km 5 hm 7 dam 7 m ÷ 3 = 2 km 8 hm 5 dam 9 m or

2.859 km

EXERCISE 5.3

A. Multiply each of the following using place-value chart.

1. 2 m 5 dm 4 cm 8 mm by 3 2. 3 g 7 dg 2 cg 9 mg by 4

3. 3 L 2 cL 6 mL by 5 4. 8 hm 7 dam 4 m by 6

5. 2 dag 4 g 5 cg 3 mg by 7 6. 1 hL 3 daL 8 L 4 dL by 8

B. Express the following in the units indicated in brackets and multiply.
1. 2 kg 5 hg 7 dag 4 g by 11 (in kg)

2. 5 hL 8 daL 7 L 2 dL by 15 (in kL)

3. 4 km 7 hm 8 m by 24 (in km)

4. 4 m 7 dm 8 cm 3 mm by 28 (in m)

5. 6 daL 8 L 3 cL by 42 (in L)
6. 3 g 5 dg 3 mg by 34 (in g)

C. Divide each of the following using place-value chart.

1. 5 m 3 dm 8 cm 4 mm by 4

2. 8 L 8 dL 4 cL 4 mL by 6

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