Page 134 - New Medley 5 Semester 2

Example 5: Subtract 2 kg 5 hg 9 dag 7 g from 8 kg 2 hg 7 dag 6 g.

Solution: By using place-value chart or By converting into kg

kg hg dag g

8 2 7 6 or 8 . 2 7 6 kg

– 2 5 9 7 – 2 . 5 9 7 kg

5 6 7 9 5 . 6 7 9 kg

Ans. 5 kg 6 hg 7 dag 9 g or 5.679 kg.

EXERCISE 5.2

A. Add the following using place-value chart.
1. 7 kL 8 hL 2 daL 9 L 6 dL, 3 kL 7 hL 4 L 8 dL and 3 hL 7 daL 2 L 6 dL

2. 4 g 2 dg 8 cg 4 mg, 9 g 6 dg 5 cg 3 mg and 8 g 5 dg 2 cg 6 mg
3. 2 kg 7 hg 5 dag 4 g 8 dg, 8 kg 3 dag 2 dg and 9 hg 7 dag 5 g 4 dg

4. 9 dam 8 m 7 dm 4 cm 5 mm, 2 m 3 dm 8 cm 4 mm and 3 dam 8 m 7 mm

B. Add the following.

1. 4 2 . 3 5 7 km 2. 3 5 6 4 . 8 kg 3. 4 2 8 . 5 3 L
9 . 2 8 3 km 1 3 0 1 . 9 kg 6 9 2 . 4 7 L

+ 3 5 . 7 3 0 km + 6 5 2 . 7 kg + 8 3 4 . 7 5 L

C. Subtract the following using place-value chart.

1. 8 m 7 dm 4 cm 5 mm from 9 m 4 dm 8 cm 2 mm

2. 4 kg 6 hg 9 dag 4 g 5 dg from 6 kg 3 hg 4 g 2 dg

3. 6 hL 3 daL 9 L 5 dL 8 cL from 9 hL 2 daL 8 L 4 dL 3 cL

4. 6 km 8 m 7 dm 3 mm from 8 km 3 hm 2 dam 4 m 5 dm 1 cm 4 mm

D. Subtract.
1. 4 2 3 . 4 5 6 kg 2. 5 2 . 7 4 3 kL 3. 8 2 3 . 5 4 6 km

– 1 5 7 . 3 8 9 kg – 9 . 2 5 8 kL – 7 9 . 8 3 0 km

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