Page 191 - New Medley 5 Semester 1

1 × 7 7 1
= = = 2
1 × 3 3 3

5 1 13 13
(b) 1 ÷ 3 = ÷
8 4 8 4
 13 4 
 Here divisoris and is itsreciprocal. 
 4 13 

1 1
13 4 1
= × =
8 13 2
2 1
4
Example 16: Find the number of rod pieces measuring m each that
5

can be cut from an iron rod measuring 20 m.

4 5 5
Solution: Number of rod pieces = 20 ÷ = 20× = 5 × 5 = 25
5 4

1
Thus, 25 pieces of the iron rod can be cut.

EXERCISE 4.5

A. Find the reciprocal of each of the following.
1 3 4
1. 3 2. 8 3. 4. 5.
5 9 15

18 2 13 1 2
6. 7. 2 8. 9. 10. 20
25 3 6 20 5

B. Evaluate the following.

4 1 2 1
1. 16 ÷ 2. 30 ÷ 1 3. 40 ÷ 4. 85 ÷ 4
9 4 3 4

1 3 2 8
5. 12 ÷ 6. 15 ÷ 7. 24 ÷ 2 8. 40 ÷
2 4 3 5

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