Page 185 - New Medley 5 Semester 1
P. 185

Multiplication of Fractions



        Multiplying a Fraction by a Whole Number

        We know that multiplication is a process of repeated addition. This is true

        for the fraction also.

                                                              2
        Consider the following multiplication                    ×  3. Let us observe this addition.
                                                              5


                            +                    +                    =



                  2                    2                   2                   6            1
                            +                    +                    =           or  1 +
                  5                    5                   5                   5             5

                           2      2     2     2 +   2 +  2      2 ×  3     6         1
        Also,                  +     +     =                 =          =      or  1
                           5      5     5           5             5        5         5

                                  2           2 ×   3     6       1
        Hence,                       ×  3  =           =      =  1
                                  5              5        5       5

        Thus, we can say that

                                                  Numeratorofthe fraction ×Whole number
         Fraction × whole number =
                                                             Denominatorofthe fraction


        Note:  Reduce  the  result  to  its  simplest  term  or  change  it  into  mixed
        fraction, if it is an improper fraction.


        Example 9:  Multiply the following.

                                    3                                 5                   1
                             (a)       by 4    (b)  12 by                   (c)  2           by 6
                                    8                                 9                   2

                                    3           3 ×   4     12      3        1
        Solution:            (a)       ×  4 =            =       =      =  1
                                    8              8         8      2        2

                                                      ×
                                           5      12 5        60      20        2
                             (b)   12 ×       =            =       =       =  6
                                           9         9         9       3        3

                                      1           5           5 ×  6      30
                             (c)   2     ×  6 =      ×  6 =            =       =  15
                                      2           2              2         2


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