Page 181 - New Medley 5 Semester 1
P. 181

Example 4:  Find the sum.
                                    2     4                  4      3       5
                             (a)       +       (b)               +      +
                                    7     7                 16     16      16

                                    2     4      2 +   4     6
        Solution:            (a)       +     =            =
                                    7     7         7        7

                                    4       3       5        4 +   3 +  5     12        3
                             (b)         +       +        =                 =      or       (in  the  lowest
                                    16     16      16             16          16        4

                                   term)

        Example 5:  Find the difference.

                                     9      5                  18       4
                             (a)         -         (b)              -
                                    14     14                  35      35

                                    9       5       9 −   5      4      2
        Solution:            (a)         −       =           =       =
                                    14     14         14        14      7

                                    18       4      18 −    4     14      2
                             (b)         −       =             =       =
                                    35      35          35        35      5

        Unlike Fractions

        We have observed that it is convenient to add or subtract like fractions.

        Therefore, to add or subtract unlike fractions, first convert them into like
        fractions and then proceed as done earlier.


        Example 6:  Add the following.
                                     7         1                 3     7           8
                             (a)         and         (b)            ,     ,and
                                    12         4                 8 12             15

                                     7      1
        Solution:            (a)         +
                                    12      4


                                   Here, the LCM of 12 and 4 is 12.

                                                     7       7 ×   1       7          1     1 ×   3      3
                                   So,                   =             =       and       =           =
                                                    12       12 ×   1     12          4     4 ×   3     12

                                               7      1      7       3       7 +  3     10       5
                                   Thus,           +     =        +      =            =      =
                                              12      4      12     12        12        12       6


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