Page 101 - New Medley 3 Semester 2
P. 101

Example 5:  Find the given fraction of the collection.


                                    1                                       1
                             (a)                                (b)
                                    4                                       5





        Solution:            (a)  There are 12 flowers in the collection. We have to find
                                    1
                                       of the collection. So, divide 12 by 4.
                                    4

                                                                                      1
                                   As                12 ÷ 4 = 3, this means   of 12 = 3 flowers.
                                                                                      4

                                                     1
                             (b)  To find out           of the group of 20 toffees, we have to
                                                     5

                                   divide 20 by 5.
                                                                             1
                                   That is,          20 ÷ 5 = 4 So,              of 20 = 4 toffees
                                                                             5


                                                EXERCISE 3.3




         A.  Shade blocks to find the given fractions.


              1.                                                  2.



                   1                                                   1
                      of 12 =                                             of          =
                   2                                                   3

                   (Hint: 12 ÷ 2 =             )






              3.                                                  4.






                   1                                                   1
                       of          =                                      of          =
                   6                                                   7



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