Page 152 - New Medley 3 Semester 1
P. 152

Property 2:  12 × 7 = 84. Also 7 × 12 = 84

                                   13 × 9 = 117. Also 9 × 13 = 117

                                   14 × 8 = 112. Also 8 × 14 = 112

                                   We get the same product in both cases.

                                   The product of two numbers is the same even if the

                                   order of numbers is changed. So, we can interchange the
                                   multiplier and multiplicand.

                                   Let A and B be the two numbers then


                                                    A × B = B × A.


               Property 3:  5 × 0 = 0                   or  0 × 5 = 0

                                   19 × 0 = 0           or  0 × 19 = 0

                                   67 × 0 = 0           or  0 × 67 = 0

                                   185 × 0 = 0  or  0 × 185 = 0

                                   The product of a number and zero (0) is zero (0).

                                   Let A be any number. Then


                                        A × 0 = 0. Also 0 × A = 0.


               Property 4:  Let us multiply 19, 27 and 38.

                                   We can multiply any two numbers at a time.

                                   9 × 27 × 38                               9 × 27 × 38

                                   = (9 × 27) × 38                           = 9 × (27 × 38)

                                   = 243 × 38                                = 9 × 1026

                                   = 9234                                    = 9234

                                   We get the same product in both cases.

                                   The product of three numbers is the same  even if  the

                                   grouping of the multiplying numbers is changed.

                                   Let A, B and C be the three numbers then.

                                        (A × B) × C = A × (B × C)


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